An object is released from some height .Exactly after one second, another object is released from the same height .The distance between the two objects exactly after 2 seconds will be?
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Since the objects are released from some height, they are in free fall and perform uniformly accelerated motion
where gravitational acceleration, g = 9.8m/s²
Let the two objects be A and B.
Let the object A be released at t = 0 s
Initial velocity, u = 0m/s
Time, t₁ = 2 s
∴Distance travelled, h₁ = 1/2 gt₁²
= 1/2*9.8 * 2²
= 9.8 * 2
= 19.6 m
Object B is released at t₂ = 1 s
Initial velocity, u = 0m/s
Time, t₃ = 2-1 = 1s
Distance travelled, h₂ =1/2 gt₃² = 1/2 * g * 1²
= 1/2 * 9.8 * 1
= 9.8/2
= 4.9 m
Thus, distance between object A and B = 19.6 - 4.9
= 14.7 m
where gravitational acceleration, g = 9.8m/s²
Let the two objects be A and B.
Let the object A be released at t = 0 s
Initial velocity, u = 0m/s
Time, t₁ = 2 s
∴Distance travelled, h₁ = 1/2 gt₁²
= 1/2*9.8 * 2²
= 9.8 * 2
= 19.6 m
Object B is released at t₂ = 1 s
Initial velocity, u = 0m/s
Time, t₃ = 2-1 = 1s
Distance travelled, h₂ =1/2 gt₃² = 1/2 * g * 1²
= 1/2 * 9.8 * 1
= 9.8/2
= 4.9 m
Thus, distance between object A and B = 19.6 - 4.9
= 14.7 m
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