Question

An object is released from the top of a tower. Find the velocity of the object at
(a) t =1 s, (b) t =2
s, (c) t =3 s after the release

Answer 1

Given :

An object is released from the top of a tower.

To Find :

Velocity of object at the end of 1, 2 and 3s.

Solution :

❖ During free fall constant acceleration due to gravity acts on the body hence equation of kinematics can be applied to solve this question$.$

» For a body falling freely under the action of gravity, g us taken positive.

First equation of kinematics :

• v = u + gt

» v denotes final velocity

» u denotes initial velocity

» g denotes acceleration

» t denotes time

A] At the end of 1st second :

➙ v = u + gt

➙ v = 0 + (10)(1)

➙ v = 10 m/s

B] At the end of 2nd second :

➙ v = u + gt

➙ v = 0 + (10)(2)

➙ v = 20 m/s

C] At the end of 3rd second :

➙ v = u + gt

➙ v = 0 + (10)(3)

➙ v = 30 m/s