Physics, asked by adityasingh1390, 10 months ago

An object is released from the top of a tower of height 19.6m. Calculate it's final velocity just before touching the ground.

Answers

Answered by dheerajkumarmaradana

1

Answer:

19.6

Explanation:

as we know v=√2gh

where g=9.8m/s² and given h= 19.6m

on substituting the values we get

v = √2×9.8×19.6

=√19.6²

= 19.6 m/s

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