An object is shot upwards, from the ground, with an initial velocity of 100m/s. How high will it be after 2.0s?
Answers
Answered by
1
Answer:
180 m
Explanation:
u = 100m/s, a = g = -10 m/s^2 (it's retardation)
t = 2 s
height (h) = ut + 1/2at^2
= 100*2 - 1/2*10*2*2 = 200 - 20 = 180 m
Similar questions