Question

An object is situated at 8 cm from a convex lens of focal length 10 cm.

Find the
position and nature of the image.


Draw a ray diagram to illustrate the formation of the image
(not to scale)​

Answer 1

-40

$From \: \: lens \: \: formula \: \: we \: \: get \: \frac{1}{f} = \frac{1}{v } - \frac{1}{u}$

$\frac{1}{f} + \frac{1}{u} = \frac{1}{v}$

$Now \: object \: distance \: from \: optic \: centre= \: 10cm \\ \frac{1}{v} = \frac{1}{10} + \frac{1}{8} </p><p> \\ \\ v = - 40cm \\ </p><p>$

Since, ve sign the image will form in front of the lens and will virtual, enlarge and erect.