Question

An object is situated at a distance of f/2 from a convex lens offocal length f . Distance of image will be

a. + (f/2) b. + (f/3) c. + (f/4) d. – f​

Answer 1

Solution:-As we know,,lens formula=

$\frac{1}{v} - \frac{1}{u} = \frac{1}{f} \\ since \: here \: u = \frac{ - f}{2} ........( negative \: side \: shows \: that \: objct \: is \: on \: \\ left \: of \: mirror \\ \frac{1}{v} - \frac{1}{ \frac{ - f}{2} } = \frac{1}{f} \\ \frac{1}{v} = \frac{1}{f} - \frac{2}{f} \\ \frac{1}{v} = - \frac{1}{f} \\v = - f \\ hence \: the \: object \: will \: be \: at \: distance \: of \: f \: \\ from \: the \: mirror \: and \: the \: negative \: sign \: shows \: \\ it \: is \: on \: left \: side$