Question

an object is situated on the left of convex lens of focal length 10cm that's distance of object 20cm another convex of focal length 12.5 is placed at distance of 30cm on the right of 1st lens find the position n magnification of the final image state the nature of image​

Answer 1

Answer:

AC = Object distance = 20 cm

BC = focal length of the lens = 10 cm

So, object is placed at the centre of curvature of the lens.

So, CD = Image distance = 20 cm

Magnification m1=1

Now DF = 10 cm.

EF = focal length of the mirror = 5 cm

So, image form the lens will be at the centre of curvature of the mirror. This image will be the object for the mirror. Image form the mirror will also be formed at the centre of curvature of the mirror and of same size.

So, magnification of the image by this mirror will be m2=1

So, total magnification = m1 x m2=1

Explanation:

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