Question

An object is slowing down on a rough horizontal plane with a deceleration of 2m/s. What is the coefficient of
kinetic friction?​

Answer 1

Answer:

Explanation:

We know that, kinetic friction = normal acting on the object (N)*friction coefficient between objects and rough surface π

By equilibrium ,the force acting on the body in backward direction = kinetic friction

And force acting on object= mass*acceleration

So force= m*2= π* m* g. (g=gravitational acceleration)

π=2/9.8

π= 0.204