An object is suspended an a spring balance if shown a weight of 40N in air and 30N in water them what is the volume of the water displaced be the object
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Answer:
Good evening dear pls mark as brilliant
Explanation:
The approximate force applied by the mass of the object is 40N- since the mass of the air being displaced is negligible when compared to the other fluids used in this question.
In case of submerging ,the volume of water displaced accounts for 20N (40−20=20N).
If a fluid with half this density is used, only half as many Newtons will be relived from the balance
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2
20N
=10N
So in second case reading of balance =40N−10N=30N
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