Question

An object is thrown at a height of 45 m from the ground (take ground as origin). What will be the height of the object after a time of 5 sec?​

Answer 1

Answer: v= 0 m/s

g= -9.8 m/s²

t= 5s

v= u + gt

0= u + -9.8 x5

-u= -49

u= 49 m/s

v²-u²= 2gs

0²- 49²= 2 x -9.8 x s

-2401= -19.6 x s

2401/19.6=s( minus sign gets cancelled)

s= 122.5 m

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