Question

an object is thrown at an angle 60 from horizontal with initial velocity 20 metre per second calculate maximum height and horizontal range​

Answer 1

Explanation:

initial velocity (u) = 20 m/s

angle of projection = 60°

let g be 10m/s^2

maximum height (Rmax) = 20^2/10= 40m

horizontal range (R) =( 20^2×3/4)/10= 30 m