Question

an object is thrown at an angle 60 from horizontal with initial velocity 20 metre per second calculate maximum height and horizontal range​

Answer 1

Explanation:

initial velocity=20m/s

angle of projection=60°

let g be 10m/s^2

maximum height (Rmax) -20^2/10=40m

horizental range(R) -(20^2×3/4)/10=30m