Question

An object is thrown form a building of 10m reaches a maximum height
40m from the ground . Calculate the initial velocity of the object​

Answer 1

  Answer:

       u = 24.49m/s

Explanation:

h = 40 -10 = 30m

g = -10m

v = 0

2gh = v² - u²

-u² = 2 × -10 × 30

u² = 600

u = 24.49m/s

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