an object is thrown from and height of h on earth and the same object is thrown on another planet whose mass and radius is twice the earth so find the height at which it is thrown so that time is same as on the earth
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the height at which it is thrown is 2h because g= GM/R²
so if M and R is twice then g= G2M/(2R)²
2GM/4R²
GM/2R² so this acceleration due to gravity is half the acceleration due to gravity on earth
and u also know that h= v²/2g
so if here g is have u get h= v²/2/g/2
h=v²/g
so if M and R is twice then g= G2M/(2R)²
2GM/4R²
GM/2R² so this acceleration due to gravity is half the acceleration due to gravity on earth
and u also know that h= v²/2g
so if here g is have u get h= v²/2/g/2
h=v²/g
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