Question

An object is thrown in the vertically upward direction with velocity u, then the maximum height attained by the object would be

Answer 1

Answer:

Hmax= u²/ 2g

here,

u is the initial velocity

g is the acceleration due to gravity

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Answer 2

Answer:

it will help

Explanation:

Solution: From 3rd equation of motion

v2 = u2

+ 2as

v = 0, a = -g

∴ 02

= u2

+ 2(-g)s

2gs = u2

s =

u2

2g