Question

an object is thrown up in air with initial velocity 20m/s.calculate the maximum height that it can reach​

Answer 1

Answer:

Initial velocity is 20m/s

maximum heighg = u^2/2g

you could get this formula from 3rd equation of motion

so putting the values we get.

H = 20 × 20 = 20m

2 × 10

so max height we get is 20 m.

I hope this will help you out

All the best.