Question

An object is thrown up vertically with an initial velocity of 100m/s. find:
(i) Time taken to reach the maximum height
(ii) Maximum height reached
(iii) Velocity after 5 seconds. (take g= 10m/s2)

Answer 1

Answer:

Given, u = 100 m/s; v = 0 m/s; a = g = -10m/s2

➡Time taken to reach maximum height

t = (v - u)/a = (0 - 100) / (-10) = 10s

➡Maximum height reached is

➡Velocity after 5 second

v = u + at = 100 + (-10 x 5)

= 50 m/s