An object is thrown up with a speed of 50 m/s . Its height from the ground after 7 s is ( take g = 10 m/s²
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h=ut-1/2(gt^2)
u=50
t=7
g=10
h=50×7-1/2(10×49)=350-245=105m
u=50
t=7
g=10
h=50×7-1/2(10×49)=350-245=105m
kanakchau:
can you more clarify it .
the body is performing motion under gravity which means it is moving with uniform acceleration g so i used the equation s=ut+1/2at^2
here s=height of object t=time a=-g becoz velocity and acceleration r in opposite direction
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