Question

an object is thrown up with a velocity of 20 metre per second find maximum height attained by it and the total time taken by it to return back ​

Answer 1

$\huge{\underline{\rm{AnsWer:-}}}$

★ Height is 20 m

★ Total time is 4 s

$\huge{\underline{\rm{ExplainaTion:-}}}$

${\underline{\underline{\bf{Given:-}}}}$

• Initial velocity(u)= 20 m/s

• Final velocity(v)= 0 m/s

• Acceleration due to gravity (g)= -10 m/s²

${\underline{\underline{\bf{To\:Find:-}}}}$

• Maximum height(h)

• Total time taken to return back.

${\underline{\underline{\bf{Solution:-}}}}$

Using third equation of motion

${ \bf{v {}^{2} - u {}^{2} = 2gh}}$

${ \sf{0 {}^{2} -( 20 ){}^{2} = 2 \times - 10 \times h}} \\ \\ { \sf{- 400 = - 20h}} \\ \\ { \sf{h = \frac{ { \cancel{- 400}}}{ - { \cancel{20} }}}} \\ \\ { \bf{h = 20 \: m}}$

Answer 2

$\huge{\bold{\red{\star{\pink{Heya!}}}}}$

Refer to the attachment ✌