Question

An object is thrown up with a velocity of 25 m/s . find (i) total time taken by the object when it reaches the ground again (ii) position of the object from ground after 4 seconds

Answer 1

Explanation:

Displacement is the minimum distance between the initial and final position of an object If a ball thrown from point A reaches point B and then return to point A, then a displacement of the ball becomes zero as it returns to its initial position.

Answer 2

Answer:

USING SECOND LAW OF MOTION S=ut+1/2at^2 put the given value as we know that a means acceleration is equal to gravity and the value of g is 9.8 ms^2 we use 10 so our calculation will be easy t=4 given u=25 given so by putting value s=(25) (4) +1/2 (10) (4)^2

s=100-(5) (16) now s=100-80 so the s=20 m