Question

An object is thrown upward at an angle of 20° above the
horizontal with a speed of 20m/s . Determine the initial
horizontal and vertical components

Answer 1

Answer:

oh yeah

Explanation:

its so simple

yeah

yeah

Answer 2

Explanation:

Given that,

Speed u=20m/s

Angle θ=300

Height h=40m

Now, along y axis

  uy=usin300

 uy=20×21

 uy=10m/s

Now, we know that

  a=−10m/s2

 s=−40m

Now, from equation of motion

  s=uyt−21gt2

 −40=10t−5t2

 5t2−10t−40=0

 t2−2t−8=0

 t2−(4−2)t−8=0

 t(t−4)+2(t−4)=0

 (t+2)(t−4)

Now, neglect of negative value

So, t=4s

Now, the range is

  R=ucos300×t

 R=20×2