Question

An object is thrown upward to a certain height with a velocity of 3m/s. If the time required to reach the height is 5 second. Calculate the height at which it was thrown .[ Hint :(g=10m/s^2 ) )(use second equation of motion)

Answer 1

s=ut+1/2at2
s=3*5+1/2*(-10)*5*5
s=-110m
the negative sign shows here the opposite direction.