an object is thrown upward to a certain height with the velocity of 3 m per second if the time required to reach the height is 5 seconds calculate the height at which it was thrown
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Given,
initial velocity,u=3m/s
time taken,t=5sec.
g=9.8m/s^2
h=?
Proof÷By 2nd equation of motion
h=ut+1/2gt^2
put the values of these
h=3×5+1/2×9.8×5×5
h=15+4.9×5×5
h=15+122.5
h=137.5m
Hence,the height will be 137.5m
Hope it is correct and it will help you friend☺☺☺!!!
initial velocity,u=3m/s
time taken,t=5sec.
g=9.8m/s^2
h=?
Proof÷By 2nd equation of motion
h=ut+1/2gt^2
put the values of these
h=3×5+1/2×9.8×5×5
h=15+4.9×5×5
h=15+122.5
h=137.5m
Hence,the height will be 137.5m
Hope it is correct and it will help you friend☺☺☺!!!
kanika200453:
thank you
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