An object is thrown upward vertically with an initial velocity of (100 m/s). Find The time it needed to return to the initial point of launching
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20s
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Explanation:
vy_initial = 100m/s
then
vy_final = vy_inital + g.t
if we assume g = -10 m/s^2 and vy_final is 0m/s (on the top of motion)
then
0 = 100-10.t
t=10second this is the time needed from launch poiint to the top of trajectory
then we will multiply it by 2
t_total = 10 . 2= 20s
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