Question

An object is thrown upwards from the ground with an initial kinetic energy of 500J.The total energy at half way point and potential energy at its greatest height are respectively​

Answer 1

56.25J

Kinetic Energy, K.E=0.5×m×v

2

K.E=0.5×0.5×15×15=56.25J

As it has 56.25 J at the initial point as total energy, at some point X,Potential Energy(P.E.) is maximum.

Total energy=P.E.+K.E.

56.25=P.E.+K.E.

As energy is conserved total energy at point X also must be 40 J.

For P.E to be maximum K.E. must be zero.

Hence P.E.=56.25J

We can come to the conclusion that potential energy will have the maximum value at maximum height.

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