Question

an object is thrown upwards in the vertical direction to a height of 10 mts calculate its velocity with what it is thrown and time taken to reach maximum height (g=9.8m\s²)​

Answer 1

Answer:

Explanation:

Given :

• Height (h) = 10 m
• Final velocity (v) = 0 m/s
• Acceleration due to gravity (g) = -9.8 m/s²

To Find :

• It's velocity & Time taken to reach maximum height.

Solution :

We know,

Height = Distance

=> 10 m = Distance

=> Distance = 10 m

Applying 3rd equation of motion,

v² = u² + 2gs

=> 0² = u² + 2 × -9.8 × 10

=> -u² = -196

=> u² = 196

=> u = 14 m/s

Applying 1st equation of motion,

v = u + at

=> 0 = 14 + -9.8 × t

=> -14 = -9.8t

=> 14 = 9.8t

=> t = 14/9.8

=> t = 1.43 s

Hence :

It's velocity & Time taken to reach maximum height is 1.43 s.