An object is thrown upwards with a speed of 25 m/s. How high will it be when the speed is 12 m/s?
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Answer:
24.05m
Explanation:
h = (v^2 - u^2)/2g. Newton third equation of motion
h = ( 12^2 - 25^2 ) / (2) (-10). g is taken negative 10 because gravity is acting in opposite direction of motion .
h = 481/20
h = 24.05 m high above the ground
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