an object is thrown upwards with speed of 50m/s.its height from the ground after 7 sec is
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1
Given,
Speed of object thrown above , u = 50m/s
Time , t = 7sec
Let object reach h hight in 7 sec from the ground ,when we thrown it with speed 50m/s .
Use formula,
S = ut + 1/2at²
here , s = h , a = -g and t = 7sec
Now, h = 50 × 7 - 1/2 × 10 × (7)²
= 350m - 245m
= 105m
Hence, height is 150m
Speed of object thrown above , u = 50m/s
Time , t = 7sec
Let object reach h hight in 7 sec from the ground ,when we thrown it with speed 50m/s .
Use formula,
S = ut + 1/2at²
here , s = h , a = -g and t = 7sec
Now, h = 50 × 7 - 1/2 × 10 × (7)²
= 350m - 245m
= 105m
Hence, height is 150m
Answered by
1
u = 50 m/s
t=7 sec
a=g=-10
s=ut + 1/2 a t^2
ans:s = 105
t=7 sec
a=g=-10
s=ut + 1/2 a t^2
ans:s = 105
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