Question

An object is thrown upwards with the velocity 20m/s.
a)How high does it rise?​

Answer 1

Answer:

The ball will rise to a point 20.4m high.

Explanation:

Formula: $v^2 -u^2 =2as$ ;  v = final velocity

                                        u = initial velocity

                                        a = acceleration

                                        s = displacement

From the problem,

u=+20m/s

v=0m/s

a = -g = -9.8 $m/s^2$

s = +h = highest point reached by the ball.

By substituting in the formula,

$=> 0^2-20^2 =2*(-9.8)*(h)\\=> 400=19.6h\\=> h=\frac{400}{19.6} = 20.4$

h = 20.4 m.