Question

An object is thrown vertically and rise to a height of 16m.(1) calculate the velocity when object thrown upward (2) time taken by the object to reach highest point

Answer 1

Final velocity, v = 0 m/s
Acc. due to gravity, g = -9.8 m/s^2
Height, h = 16m
From 3rd equation of motion,
${v}^{2} - {u}^{2} = 2gh\\ {(0)}^{2} - {u}^{2} = 2 \times - 9.8 \times 16 \\ 0 - {u}^{2} = - 31.36 \\ { - u}^{2} = - 31.36 \\ u = \sqrt{31.36} \\ u = 5.6m$
From 1st equation of motion,
v = u + at
0 = 5.6 + (-9.8) × t
0 = 5.6 -9.8t
-5.6 = -9.8t
5.6 / 9.8 = t
0.57s = t