Question

An object is thrown vertically up with velocity 'u' reaches maximum height in time 't' .the average velocity during this time isa) u/2b) 2u/gc) u/g d) u square/ 4g​

Answer 1

At height H above the ground the final velocity v becomes zero

V=U-gt

U=gt

T=u/g

I hope this helps ( ╹▽╹ )