Question

An object is thrown vertically up with velocity 'u' reaches maximum height in time
t'. The average velocity during this time is
a) u/2
d) u/g
b) 2u/g
c) u/4g

the correct answer is u/2 I need the explanation please ​

Answer 1

Answer:

u/2

Explanation:

At the maximium height the velocity becomes zero.so the average velocity is( final + initial)/2

that is =(u+0)/2

Answer 2

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