an object is thrown vertically upward and raise to the height of 10 cm calculate the velocity with which the object was thrown upward and the time taken by an object to reach at the highest point
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Let velocity of object is u
we know, at 10m height object will be rest .
so, final velocity = 0
A/C to kinematics equations,
v² = u² + 2aS
0 = u² +2(-g) × 10
0 = u² - 2 × 100
u² = 200
u = 10√2 m/s
Time taken by the object to reach the highest point is t
v = u + at
0 = 10√2 - 10t
t = 10√2/10 sec
t = √2 sec
we know, at 10m height object will be rest .
so, final velocity = 0
A/C to kinematics equations,
v² = u² + 2aS
0 = u² +2(-g) × 10
0 = u² - 2 × 100
u² = 200
u = 10√2 m/s
Time taken by the object to reach the highest point is t
v = u + at
0 = 10√2 - 10t
t = 10√2/10 sec
t = √2 sec
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