Question

An object is thrown vertically upward and rise to a height of 13.7m Calculate. a) The velocity with which the object is thrown upward. b)The time taken by the object to rich the highest point.​

Answer 1

Answer:

1) v=3√30

2) t=0.3√30

Explanation:

Plotting:

s=13.7 m

u=0

g=10 m/s^2

t,v=??

1) We know, v^2-u^2=2*g*s

=>v^2=2*g*s+u^2

=>v^2=2*9.85*13.7 + 0

=>v^2=270

=>v=√270=3√30

2)v=u+g*t

=>3√30=0+10*t

=>t=0.3√30