Question

an object is thrown vertically upward and rises to a height of 10m . calculate (1) the velocity with which the object was thrown upwards and (2 )the time taken by the object to reachthe highest point ​

Answer 1

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Explanation:

Answer 2

Solution:-

Let the Initial Velocity be "x" m/s.

Since, Object has rised to it's Highest point.

=) Final Velocity ( v ) = 0 m/s

Given :-

• v = 0
• u = x m/s
• s = 10m
• a = -g = -10 m/s²
• T = t

Now,

v² = u² + 2as

=) 0 = x² + 2(-10)(10)

=) x = √200

=) x = 10√2 m/s

Hence, Initial Velocity of the Object = 10√2 m/s.

(ii) Time taken to reach the Height.

=) v = u + at

=) 0 = 10√2 - 10t

=) 10t = 10√2

=) t = √2 = 1.41 seconds.

Solved!!