An object is thrown vertically upward and rises to the height of 10m. Calculate the velocity of the object which was thrown upwards and the time take by to object to reach the height point
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Explanation:
h=10m , v(final velocity)= 0m/s ,g=(-9.8)m/s^2
we have to find initail velocity u=? and time t=?
From third equation of motion
v^2=u^2+2gh
0=u^2+2*(-9.8)*10
u^2= 2*9.8*10
u^2=196
u=√196
u=14 m/s
From first equation of motion
v=u+gt
t=(v-u)/g
t= (0-14)/(-9.8)
t=(-14)/(-9.8)
t=1.42 seconds
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