An object is thrown vertically upward from a height of h0 ft with an initial speed of v0 ft/sec. Its height h (in feet) after t seconds is given by
h= -16t² + v0t + h0. Given this, if it is thrown vertically upward from the ground with an initial speed of 64 ft/sec,
(a) At what time will the height of the ball be 15 ft? (two answers)
(b) How long will it take for the ball to reach 63 ft?
Answers
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12
Answer:
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it should be negligible
Answered by
7
Answer:
Step-by-step explanation:
h=16t^2+64t+1
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