an object is thrown vertically upward Rises to the height of 10 metre calculate the velocity which the object was through upward
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Answered by
2
heyy...
here
g= -9.8 m/s^2 because the acceleration is in opposite direction
v =0 because at a point it will stop
h=10
u=?
here
g= -9.8 m/s^2 because the acceleration is in opposite direction
v =0 because at a point it will stop
h=10
u=?
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kshankar:
answer this question please time taken by the object to reach the highest point from same question
thank you very much
okk
to find time ...apply the formula v = u +gt where (v=0,,,,u = 14 ,,,,g = -9.8,,,,,t=??)
Answered by
1
u = ?
v = 0m/s
a=g=10m/s^2
s=h= 10m
2as =v^2 - u^2
2×10×10 = 0 - u^2
200= -u^2
√200 = u
14.142m/s = u
v = 0m/s
a=g=10m/s^2
s=h= 10m
2as =v^2 - u^2
2×10×10 = 0 - u^2
200= -u^2
√200 = u
14.142m/s = u
thank you very much
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