An object is thrown vertically upward to a height of 12m . Calculate its velocity with which it was thrown upwards. Time taken by the object to reach a height of 12m
Answers
Answer:-
→ The object was thrown upwards with a velocity of 15.34 m/s .
→ Required time taken is 1.56 s .
Explanation:-
Max height reached = 12 m
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Since, the object is thrown vertically upwards. So in this case :-
• Velocity of the object at the highest point will be zero. [ v = 0 ]
• Acceleration due to gravity will be -9.8 m/s² as the object is going against the gravity.
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By using 3rd equation of motion, we get :-
⇒ v² = u² + 2gh
⇒ 0 = u² + 2(-9.8)12
⇒ 0 = u² - 235.2
⇒ u² = 235.2
⇒ u = √235.2
⇒ u = 15.34 m/s
Now, by using the 1st equation of motion :-
⇒ v = u + gt
⇒ 0 = 15.34 + (-9.8)t
⇒ -15.34 = -9.8t
⇒ t = -15.34/-9.8
⇒ t = 1.56 s
Answer:
Given :-
- An object is thrown vertically upward to a height of 12 m.
To Find :-
- Calculate it's velocity with which it was thrown upwards.
- Time taken by the object to reach a height of 12 m.
Formula Used :-
➲ v² = u² + 2gh
➲ v² = u + gt
where,
- v = Final velocity
- u = Initial velocity
- g = Acceleration due to gravity
- h = Height
Solution :-
⓵ To find velocity with which it was thrown upwards :
Given :
- Final velocity (v) = 0 m/s
- Acceleration due to gravity (g) = - 9.8 m/s²
- Height (h) = 12 m
According to the question by using the formula we get,
↦ (0)² = u² + 2 × (- 9.8) × 12
↦ 0 = u² + 24 × (- 9.8)
↦ 0 = u² - 235.2
↦ √235.2 = u
↦ 15.34 = u
➠ u = 15.34 m/s
∴ The velocity with which it was thrown upwards is 15.34 m/s.
⓶ Time taken by the object to reach a height of 12 m :
Given :
- Final velocity = 0 m/s
- Initial velocity = 15.34 m/s
- Acceleration due to gravity = - 9.8 m/s²
According to the question by using the formula we get,
↦ 0 = 15.34 + (- 9.8) × t
↦ 0 = 15.34 - 9.8 × t
↦ 0 = 15.34 - 9.8t
↦ - 15.34 = - 9.8t
↦ - 15.34/9.8 = t
↦ - 1.56 = t
➦ t = 1.56 seconds
∴ The time taken by the object to reach a height of 12 m is 1.56 seconds.