Question

An object is thrown vertically upward to a height of 12m . Calculate its velocity with which it was thrown upwards. Time taken by the object to reach a height of 12m​

Answer 1

v^2- u^2 = 2as

0 - u^2 = 2 x -g x s       ( upward motion)

-u^2 = 2 x (-10) x 12

u^2 = 20 x 12

u^2 = 240

u = 240^1/2

= 15.4 approx

v= u + at

0 = 15.4 + (-10) t

- 15.4 = -10t

1.54 = t

Answer 2

Explanation:

4\sqrt{15}

15

m/s

Explanation:

v = 0 m/s

a = -10 m/s^{2}s

2

(approx.)

S = 12 m

u = ?

2aS = v^{2} - u^{2}v

2

−u

2

2 × (-10) × 12 = 0 - u^{2}u

2

- u^{2}u

2

= 24 × -10

u^{2}u

2

= 240

u = \sqrt{240}

240

u = 4\sqrt{15}

15m/s.

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