Question

an object is thrown vertically upward velocity 30m/s find the height attain by the object if the acceleration due to gravity is 10m/s2​

Answer 1

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★ Sᴏʟᴜᴛɪᴏɴ :-

Finding height using,

H = u²/2g

Where

• H → Height = ?
• u → initial velocity = 30 m/s
• g → acceleration due to gravity = - 10 m/s²

Substituting the values we have ,

⇒ H = 30²/2(10)

⇒ H = 900/20

⇒ H = 90/2

⇒ H = 45 m

Hence , height attained by the object = 45 m

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★ Dᴇʀɪᴠᴀᴛɪᴏɴ ᴏF Tʜᴇ Fᴏʀᴍᴜʟᴀ :-

♦ H = u²/2g ♦

Deriving the given formula using the second equation of motion.

• v² - u² = - 2gh

Here , the final velocity will be zero because the object will go upward , stops there only for some time and comes back . So , final Velocity will be zero

Simplifying

➩ 0² - u² = - 2gH

➩ - u² = - 2gH

➩ u² = 2gH

➩ H = u²/2g

Hence , derived !

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Answer 2

Given : An object is thrown vertically upward velocity 30 m/s.

　

To find : What is the height attain by the object if the acceleration due to gravity is 10 m/s².

　

Solution : We can solve this question by applying “Height formula” in Physics.

　

Formula :

★ Height = Initial velocity²/2 Gravitational acceleration.

　　　　　　　　Or

★ H = u²/2 g.

　

Calculations :

$:\implies\sf{Height = \dfrac{30^{2}}{2 \times 10}}$

　

$:\implies\sf{Height = \dfrac{900}{20}}$

　

$:\implies{\sf{\underline{\boxed{\sf{Height = 45 \: m}}}}}$

　

Therefore, 45 m is the height attained by the object.