Question

. An object is thrown vertically upward with a
velocete of 20ms-1. find:
1. the distance travelled by the object to reach the
highest point.
2.the time taken by the object to reach the highest point.
(Take g = 10 mi-2)​

Answer 1

Answer:

1)Max height=u^2/2g

=20*20/20=20m

2)time = u/g (2u/g for reaching bottom as well)

=20/10=2sec

pls mark brainliest