Question

An object is thrown vertically upward with a velocity u. The greatest height h to which it will rise before falling back is given by​

Answer 1

Answer:

answer in attachment

Answer 2

Answer:

Maximum height  = u² / 2g

Explanation:

Equation for motion for a vertically ascending body

v² - u² = - 2gh   (Negative sign for "2gh" because the body is moving opposite to "g" i.e. acceleration due to gravity which always acts downwards)

v = 0 (as the body will stop for a fraction of time when it reaches the top)

- u² = - 2gh

u² = 2gh (negative sign will get cancelled because it is on both sides)

u² / 2g = h

Hence, the maximum height which the object can reach will be u² / 2g

Hope you found this answer helpful, thank you for asking this question

please mark as brainliest