Question

An object is thrown vertically upward with an initial velocity of 6 m/s. Find the height up to which it will rise above the ground level.(g=10 meter per second square)​

Answer 1

$\bf\huge{\underline{\underline{Question:-}}}$

An object is thrown vertically upward with an initial velocity of 6 m/s. Find the height up to which it will rise above the ground level . ( g = 10 m/sec.sq )

$\bf\huge{\underline{\underline{Given:-}}}$

• Initial velocity of object (u) = 6m/sec
• velocity of object at maximum height (v) = 0
• g = 10 m/sec²

$\bf\huge{\underline{\underline{Find:-}}}$

• Height of object which it will rise ?

$\bf\huge{\underline{\underline{Answer:-}}}$

• The maximum height reach by object from the ground level is 0.5 m

$\bf\large{\underline{\underline{Step\:by\:step\: explanation:-}}}$

$\sf → v^2-u^2=2gh$

$\sf → 0^2-6^2=2×10×h$

$\sf → 0-36=20h$

$\sf → 36 = 20h$

$\sf → h = \dfrac{\cancel{20}}{\cancel{36}}$

$\sf{\boxed{\red{h=0.5m}}}$

$\bf\huge{\underline{\underline{Hence:-}}}$

• The maximum height reach by object from the ground level is 0.5 m

Answer 2

Answer:

HEY PRINCE

TODAY WAS YOUR EXAM

?

u = 6m/s

v=0

v= u+at

0= 6+10t

6=10t (minus will cut)

t= 6/10 = 3/5 sec

S= ut +1/2 at²

6 x 3/5 + 1/2 x - 10 x 9/25(sq of 3/5)

Answer Will Be 1.8 m