Question

An object is thrown vertically upward with velocity 5 m/s. What is the maximum height reached by the object? Use g = 10 m/s2

Answer 1

Answer:

1.25 m

Explanation:

v (final velocity) = 0 m/s

u (initial velocity) = 5 m/s

a (deceleration/acceleration) = 10 m/s²

We need to find s (displacement), so:

v² = u² + 2as

0 = 5² + (2*10s)

⇒ 0 = 25 + 20s

⇒ s = -25/20 = -1.25m

Since the object was decelerating, we have gotten a negative value. However, the distance travelled by the object will be positive.

Hence, the maximum height reached by the object is 1.25 m.