Question

An object is thrown vertically upwards and raises to an height of 20 m. Calculate i. Velocity with which the object thrown upwards. ii. The time taken by the object to reach the highest point. (take g = 10 m/s2

Answer 1

Time taken to reach the highest point is 2 seconds

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Answer 2

Answer:

u=20m/s & t=2s

Explanation:

given: v=0, s=20m, g=10 (but we should take g=-10 because the object is thrown opposite to gravitational acceleration )therefore g(in this case) g=a= -10m/s^2

u=? & t=?

soln(i): according to newton's 3rd law

v^2=u^2+2as

0=u^2+2×-10×20

0=u^2-400

400=u^2

therefore u=20m/s

soln (ii): according to newton's 1st law v=u+at

0=20+(-10)t (u that is calculated in previous question)

10t=20

t=20÷10

therefore ,t=2s