Physics, asked by yasirmalik7235, 8 months ago

An object is thrown vertically upwards and rises to a height of 10 m. Calculate the velocity with which the object was thrown upwards?​

Answers

Answered by BrainlyConqueror0901
19

\blue{\bold{\underline{\underline{Answer:}}}}

\green{\tt{\therefore{Initial\:velocity=10\sqrt{2}\:m/s}}}

\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}

 \green{\underline \bold{Given:}} \\  \tt:  \implies Height= 10\:m \\  \\ \tt:  \implies Final \: velocity( v ) = 0 \: m/s \\\\ \tt:  \implies Acceleration(a) =- 10 \: m/s^{2} \\  \\   \red{\underline \bold{To \: Find:}}\\ \tt:  \implies Initial\:velocity(u) = ?\\\\ \tt:\implies Distance\:travelled=?

• According to given question :

 \bold{As \: we \: know \: that} \\  \tt:  \implies  {v}^{2}   =  {u}^{2}  + 2as \\  \\ \tt:  \implies  {0}^{2}  =  {u}^{2}  + 2 \times ( - 10) \times 10 \\  \\ \tt:  \implies  -  {u}^{2}  =  - 200 \\  \\ \tt:  \implies  {u}^{2}  = 200 \\  \\ \tt:  \implies u =  \sqrt{200}  \\  \\  \green{\tt:  \implies u = 10 \sqrt{2}  \: m/s}\\\\ \green{\tt\therefore Initial\:velocity\:of\:object\:is\:10\sqrt{2}\:m/s}

Answered by Saby123
4

</p><p>\tt{\huge{\pink{Hello !!! }}}

</p><p>\tt{\red{Question \: - }}

An object is thrown vertically upwards and rises to a height of 10 m. Calculate the velocity with which the object was thrown upwards?

We Know That

 \tt{ \purple{ \boxed{ \boxed{ \implies{ {v}^{2} =  {u}^{2}  + 2as }}}}}

Substituting the values and solving we get :

</p><p>\tt{\orange{\implies{u = 10 \sqrt{2}  \:m/s. }}}

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