An object is thrown vertically upwards and rises to a height of 45m. Calculate(1) the velocity with which the object was thrown upwards and (2) the time taken by the object to reach the highest point.(3) the time for which it was in the air
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height=45m
velocity with which object was thrown upwards is v
1)v=√2gh
=√2×10×45
=√900
=30m/s
2)time taken to reach highest point=time of ascent
=v/g
=30/10
=3sec
3)time for which it was in air =time of flight
=2v/g
=2×30/10
=6sec
Explanation:
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