Question

An object is thrown vertically upwards and rises to a height of 45m. Calculate(1) the velocity with which the object was thrown upwards and (2) the time taken by the object to reach the highest point.(3) the time for which it was in the air

I will mark brainliest whoever answers correctly
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Answer 1

Answer:

u = 30m/s

T = 3 sec

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Answer 2

Given, h = 45 m, a = -g = - 9.8 m/s², v = 0 (At the highest point of reach, final velocity is zero)

(1) We know that, v² = u²+2gh

=> 0 = u² - 2×9.8×45

=> u² = 882

=> u = √882 = 29.7 (approx.)

(2) Time taken by the body to reach the highest point (t) = u/g = 29.7/9.8 = 3.03 seconds (approx.)

(3) The time for which it was in the air = 2u/g = 6.06 seconds (approx.)