Question

An object is thrown vertically upwards and rises to a height of 10m. Calculate(1) the velocity with which the object was thrown upwards and (2) the time taken by the object to reach the highest point.3) total time for which object remains in air

Answer 1

Explanation:

s = u*t + 0.5*a*t²

v²-u²=2a*s

v= 0, a= -10, s = 10

therefore, u² = 2*10*10

u = 10√2 m/s

v= u+at

0 = 10√2 - 10*t

t = √2 s

Total time = 2√2